4x^2=10.2

Solution for 4x^2=10.2 equation:

4x^2=10.2

We move all terms to the left:

4x^2-(10.2)=0

We add all the numbers together, and all the variables

4x^2-10.2=0

a = 4; b = 0; c = -10.2;
Δ = b2-4ac
Δ = 02-4·4·(-10.2)
Δ = 163.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{163.2}}{2*4}=\frac{0-\sqrt{163.2}}{8}
=-\frac{\sqrt{}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{163.2}}{2*4}=\frac{0+\sqrt{163.2}}{8}
=\frac{\sqrt{}}{8}
$